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import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main {
public static void main(String[] args) {
String regex = "\\$\\{(.*?)\\}";
Map<String, Object> map = new HashMap<>();
map.put("name", "jake");
map.put("age", 18);
map.put("work", "学生");
map.put("color", "");
String mes = MessUtil.getMes("我的朋友是${name},他今年${age}岁,是一名${work},他喜欢的颜色是${color}!", regex, "${", "}", map);
System.out.println(mes);
}
}
class MessUtil {
/**
* 组装信息
* @param soap 原始信息
* @param regex 条件 占位符
* @param startStr 删除掉的内容
* @param endStr 删除掉的内容
* @param map 根据原始信息占位符中的内容作为key,获取替换进占位符中的内容
* @return
*/
public static String getMes(String soap, String regex, String startStr, String endStr, Map<String, Object> map) {
List<String> subUtil = getSubUtil(soap, regex);
for (String s : subUtil) {
if (map.containsKey(s) && null != map.get(s)) {
soap = soap.replace(startStr + s + endStr, map.get(s).toString());
// 配套另一篇文章,计算器数字计算,可用此办法
// soap = soap.replace(startStr + s + endStr, "(0+"+map.get(s).toString()+")");
}
}
return soap;
}
private static List<String> getSubUtil(String soap, String regex) {
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(soap);
List<String> list = new ArrayList<>();
int i = 1;
while (matcher.find()) {
list.add(matcher.group(i));
}
return list;
}
}
输出结果为
- 01
我的朋友是jake,他今年18岁,是一名学生,他喜欢的颜色是!
摘自https://blog.csdn.net/qq_39922867/article/details/103736265